Question
A car covers 80 km in 2 hours. and a train travels 180 km in 3 hours. What is the ratio of the speed of the car to that of the train?
Solution
Correct
option
is 2 : 3
Speed = distance / time $\therefore$ Speed of car : Speed of train =$ \dfrac {80 }2 :\dfrac {180 }3 = 40 : 60 = 2 : 3 $
Speed = distance / time $\therefore$ Speed of car : Speed of train =$ \dfrac {80 }2 :\dfrac {180 }3 = 40 : 60 = 2 : 3 $
Question
A bullock cart has to cover 120 distances in 15 hours. If it completes half the journey in $\dfrac 35$ time, then at what speed will the bullock cart have to be driven to complete the remaining journey in the remaining time?
Solution
Correct
option
is 10 km/h
Remaining time $\dfrac 25 \times 15 =6 $hours Required speed = $\dfrac {60 }6 = 10 $ kmph
Remaining time $\dfrac 25 \times 15 =6 $hours Required speed = $\dfrac {60 }6 = 10 $ kmph
Question
A man reaches his office 10 minutes late at his usual speed, how much time does he usually take to cover this distance ?
Solution
Correct
option
is 30 minute
Since he moves at $\dfrac34$ of his speed So $\dfrac43$ will take time So $\dfrac43 x-x=10$ $x=30$ min
Since he moves at $\dfrac34$ of his speed So $\dfrac43$ will take time So $\dfrac43 x-x=10$ $x=30$ min
Question
A person goes to his office at a speed of 60 km/d0 and is returned at a speed of 40 km/do. Find the distance if it takes 5 hour ?
Solution
Correct
option
is 224
From the formula $ =\dfrac{xy}{x+y}\times t$ we are able to calculate half the distance so $=\dfrac{24\times21}{24+21}\times10=112$ so the full distance $= 2\times112=224$ km
From the formula $ =\dfrac{xy}{x+y}\times t$ we are able to calculate half the distance so $=\dfrac{24\times21}{24+21}\times10=112$ so the full distance $= 2\times112=224$ km
Question
A train 150 m long takes 30 seconds to cross a bridge 500 m long. How much time will this train take to cross a platform 370 meters long?
Solution
Correct
option
is 24 seconds
Speed of train =$\dfrac {150 + 500}{30}= \dfrac {650}{30}=\dfrac {65}3$m/second Required time =distance /time =$\left (\dfrac{150 +370}{65}\right)\times3= 24$ seconds
Speed of train =$\dfrac {150 + 500}{30}= \dfrac {650}{30}=\dfrac {65}3$m/second Required time =distance /time =$\left (\dfrac{150 +370}{65}\right)\times3= 24$ seconds
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