Question
Amar, Bhavan, chetan and Dinesh have a total of 150 with them, Amar has one-fourth of the total amount with the other. The amount with Amar (int)is:
37.5
30
25
20
Solution
Correct
option
is 30
Let Bhawan, Chetan and Dinesh have total Rs.x
near immortal = $\dfrac x4$
Total amount = $x + \dfrac x4 = 150$
5x = 600
x = 120
Amount of immortal = $\dfrac x4 = \dfrac{120}{4}= 30$
Question
A is 60% more than B, C is 35% less than D and D is 30% more than A, Which of the following is true?
169 B = 125 C
25 B = 13 C
13 B = 25 C
125 = 169 C
Solution
Correct
option
is 169 B = 125 C
प्रश्नानुसार,
$B \times \dfrac{160}{100} = A$
$B \times \dfrac {160}{100}\times \dfrac{130}{100} = D$
$B \times \dfrac {160}{100}\times \dfrac{130}{100} \times \dfrac{65}{100}= C$
169B = 125C
Question
If X is 80% more than Y, then Y is how much percentage less than X?
61.33%
80%
33.3%
44.44%
Solution
Correct
option
is 44.44%
X की तुलना में Y में प्रतिशत कमी
$=\left(\dfrac{80}{100 + 80}\right)\times 100$
$ = \dfrac{80}{180}\times 100$
$ = 44.44%$
Question
A is 20% less than B. B is 10% less than C. C is 30% more than D. If D is 400, then what is the value of A?
374.4
368.6
382.2
354.2
Solution
Correct
option
is 374.4
दिया गया है -
D = 40
$\therefore C = 400\times \dfrac{130}{100} = 520$
$\therefore B = 520\times \dfrac{90}{100} = 468$
$\therefore A = 468\times \dfrac{80}{100} = 374.4$
Question
What is the difference between 0.9 and 0.9%?
0.981
0.891
0.198
8.91
Solution
Correct
option
is 0.891
अभीष्ट अन्तर = 0.9 - $\dfrac{0.9}{100}$
= 0.9-0.009
= 0.900-0.009
- = 0.891